-12y+15=3(4y-5)

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Solution for -12y+15=3(4y-5) equation: 



-12y+15=3(4y-5)

We move all terms to the left:

-12y+15-(3(4y-5))=0



We calculate terms in parentheses: -(3(4y-5)), so:

3(4y-5)

We multiply parentheses

12y-15

Back to the equation:

-(12y-15)



We get rid of parentheses

-12y-12y+15+15=0

We add all the numbers together, and all the variables

-24y+30=0

We move all terms containing y to the left, all other terms to the right

-24y=-30

y=-30/-24

y=1+1/4

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