-12z+4=(z-9)+30+z

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Solution for -12z+4=(z-9)+30+z equation:



-12z+4=(z-9)+30+z
We move all terms to the left:
-12z+4-((z-9)+30+z)=0
We calculate terms in parentheses: -((z-9)+30+z), so:
(z-9)+30+z
determiningTheFunctionDomain (z-9)+z+30
We add all the numbers together, and all the variables
z+(z-9)+30
We get rid of parentheses
z+z-9+30
We add all the numbers together, and all the variables
2z+21
Back to the equation:
-(2z+21)
We get rid of parentheses
-12z-2z-21+4=0
We add all the numbers together, and all the variables
-14z-17=0
We move all terms containing z to the left, all other terms to the right
-14z=17
z=17/-14
z=-1+3/14

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