-12z+6(z-5)=-8z

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Solution for -12z+6(z-5)=-8z equation: 



-12z+6(z-5)=-8z

We move all terms to the left:

-12z+6(z-5)-(-8z)=0

We multiply parentheses

-12z+6z-(-8z)-30=0

We get rid of parentheses

-12z+6z+8z-30=0

We add all the numbers together, and all the variables

2z-30=0

We move all terms containing z to the left, all other terms to the right

2z=30

z=30/2

z=15

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