-13(d+1)=3(d+2)

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Solution for -13(d+1)=3(d+2) equation:


Simplifying
-13(d + 1) = 3(d + 2)

Reorder the terms:
-13(1 + d) = 3(d + 2)
(1 * -13 + d * -13) = 3(d + 2)
(-13 + -13d) = 3(d + 2)

Reorder the terms:
-13 + -13d = 3(2 + d)
-13 + -13d = (2 * 3 + d * 3)
-13 + -13d = (6 + 3d)

Solving
-13 + -13d = 6 + 3d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-3d' to each side of the equation.
-13 + -13d + -3d = 6 + 3d + -3d

Combine like terms: -13d + -3d = -16d
-13 + -16d = 6 + 3d + -3d

Combine like terms: 3d + -3d = 0
-13 + -16d = 6 + 0
-13 + -16d = 6

Add '13' to each side of the equation.
-13 + 13 + -16d = 6 + 13

Combine like terms: -13 + 13 = 0
0 + -16d = 6 + 13
-16d = 6 + 13

Combine like terms: 6 + 13 = 19
-16d = 19

Divide each side by '-16'.
d = -1.1875

Simplifying
d = -1.1875

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