-13(y+1)+5(4y-7)=6(y-3)+9

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Solution for -13(y+1)+5(4y-7)=6(y-3)+9 equation: 



-13(y+1)+5(4y-7)=6(y-3)+9

We move all terms to the left:

-13(y+1)+5(4y-7)-(6(y-3)+9)=0

We multiply parentheses

-13y+20y-(6(y-3)+9)-13-35=0



We calculate terms in parentheses: -(6(y-3)+9), so:

6(y-3)+9

We multiply parentheses

6y-18+9

We add all the numbers together, and all the variables

6y-9

Back to the equation:

-(6y-9)



We add all the numbers together, and all the variables

7y-(6y-9)-48=0

We get rid of parentheses

7y-6y+9-48=0

We add all the numbers together, and all the variables

y-39=0

We move all terms containing y to the left, all other terms to the right

y=39

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