-13(y+1)+5(4y-7)=6(y-3)+9

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Solution for -13(y+1)+5(4y-7)=6(y-3)+9 equation:



-13(y+1)+5(4y-7)=6(y-3)+9
We move all terms to the left:
-13(y+1)+5(4y-7)-(6(y-3)+9)=0
We multiply parentheses
-13y+20y-(6(y-3)+9)-13-35=0
We calculate terms in parentheses: -(6(y-3)+9), so:
6(y-3)+9
We multiply parentheses
6y-18+9
We add all the numbers together, and all the variables
6y-9
Back to the equation:
-(6y-9)
We add all the numbers together, and all the variables
7y-(6y-9)-48=0
We get rid of parentheses
7y-6y+9-48=0
We add all the numbers together, and all the variables
y-39=0
We move all terms containing y to the left, all other terms to the right
y=39

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