-13(z+1)+5(4z-3)=6(z-4)+10

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Solution for -13(z+1)+5(4z-3)=6(z-4)+10 equation:


-13 (z+1)+5 (4z-3)=6 (z-4)+10

We simplify the equation to the form, which is simple to understand 
-13(z+1)+5(4z-3)=6(z-4)+10

Reorder the terms in parentheses
+(-13z-13)+5*(4z-3)=6*(z-4)+10

Remove unnecessary parentheses
-13z-13+5+*(+4z-3+)=+6+*(+z-4+)+10

Reorder the terms in parentheses
-13z-13+(+20z-15)=6*(z-4)+10

Remove unnecessary parentheses
-13z-13+20z-15=+6+*(+z-4+)+10

Reorder the terms in parentheses
-13z-13+20z-15=+(+6z-24)+10

Remove unnecessary parentheses
-13z-13+20z-15=+6z-24+10

We move all terms containing z to the left and all other terms to the right. 
-13z+20z-6z=-24+10+13+15

We simplify left and right side of the equation. 
+1z=+14

We divide both sides of the equation by 1 to get z. 
z=14

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