-13(z+1)+5(4z-4)=6(z-3)+12

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Solution for -13(z+1)+5(4z-4)=6(z-3)+12 equation:



-13(z+1)+5(4z-4)=6(z-3)+12
We move all terms to the left:
-13(z+1)+5(4z-4)-(6(z-3)+12)=0
We multiply parentheses
-13z+20z-(6(z-3)+12)-13-20=0
We calculate terms in parentheses: -(6(z-3)+12), so:
6(z-3)+12
We multiply parentheses
6z-18+12
We add all the numbers together, and all the variables
6z-6
Back to the equation:
-(6z-6)
We add all the numbers together, and all the variables
7z-(6z-6)-33=0
We get rid of parentheses
7z-6z+6-33=0
We add all the numbers together, and all the variables
z-27=0
We move all terms containing z to the left, all other terms to the right
z=27

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