-13(z+1)+5(4z-4)=6(z-6)+14

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Solution for -13(z+1)+5(4z-4)=6(z-6)+14 equation: 



-13(z+1)+5(4z-4)=6(z-6)+14

We move all terms to the left:

-13(z+1)+5(4z-4)-(6(z-6)+14)=0

We multiply parentheses

-13z+20z-(6(z-6)+14)-13-20=0



We calculate terms in parentheses: -(6(z-6)+14), so:

6(z-6)+14

We multiply parentheses

6z-36+14

We add all the numbers together, and all the variables

6z-22

Back to the equation:

-(6z-22)



We add all the numbers together, and all the variables

7z-(6z-22)-33=0

We get rid of parentheses

7z-6z+22-33=0

We add all the numbers together, and all the variables

z-11=0

We move all terms containing z to the left, all other terms to the right

z=11

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