-13+2b=3-4(1-b)

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Solution for -13+2b=3-4(1-b) equation:



-13+2b=3-4(1-b)
We move all terms to the left:
-13+2b-(3-4(1-b))=0
We add all the numbers together, and all the variables
2b-(3-4(-1b+1))-13=0
We calculate terms in parentheses: -(3-4(-1b+1)), so:
3-4(-1b+1)
determiningTheFunctionDomain -4(-1b+1)+3
We multiply parentheses
4b-4+3
We add all the numbers together, and all the variables
4b-1
Back to the equation:
-(4b-1)
We get rid of parentheses
2b-4b+1-13=0
We add all the numbers together, and all the variables
-2b-12=0
We move all terms containing b to the left, all other terms to the right
-2b=12
b=12/-2
b=-6

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