-13-5(-z-2)=-8(-2z+10)

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Solution for -13-5(-z-2)=-8(-2z+10) equation: 



-13-5(-z-2)=-8(-2z+10)

We move all terms to the left:

-13-5(-z-2)-(-8(-2z+10))=0

We add all the numbers together, and all the variables

-5(-1z-2)-(-8(-2z+10))-13=0

We multiply parentheses

5z-(-8(-2z+10))+10-13=0



We calculate terms in parentheses: -(-8(-2z+10)), so:

-8(-2z+10)

We multiply parentheses

16z-80

Back to the equation:

-(16z-80)



We add all the numbers together, and all the variables

5z-(16z-80)-3=0

We get rid of parentheses

5z-16z+80-3=0

We add all the numbers together, and all the variables

-11z+77=0

We move all terms containing z to the left, all other terms to the right

-11z=-77

z=-77/-11

z=+7

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