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-130x+120x^2+25=0
a = 120; b = -130; c = +25;
Δ = b2-4ac
Δ = -1302-4·120·25
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4900}=70$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-130)-70}{2*120}=\frac{60}{240} =1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-130)+70}{2*120}=\frac{200}{240} =5/6 $
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