-131=-5x(3x-8)+6x

Solution for -131=-5x(3x-8)+6x equation:

-131=-5x(3x-8)+6x

We move all terms to the left:

-131-(-5x(3x-8)+6x)=0


We calculate terms in parentheses: -(-5x(3x-8)+6x), so:

-5x(3x-8)+6x

We add all the numbers together, and all the variables

6x-5x(3x-8)

We multiply parentheses

-15x^2+6x+40x

We add all the numbers together, and all the variables

-15x^2+46x

Back to the equation:

-(-15x^2+46x)


We get rid of parentheses

15x^2-46x-131=0

a = 15; b = -46; c = -131;
Δ = b2-4ac
Δ = -462-4·15·(-131)
Δ = 9976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9976}=\sqrt{4*2494}=\sqrt{4}*\sqrt{2494}=2\sqrt{2494}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-46)-2\sqrt{2494}}{2*15}=\frac{46-2\sqrt{2494}}{30}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-46)+2\sqrt{2494}}{2*15}=\frac{46+2\sqrt{2494}}{30}
$