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-13=5/2(2+8x)-2
We move all terms to the left:
-13-(5/2(2+8x)-2)=0
Domain of the equation: 2(2+8x)-2)!=0We add all the numbers together, and all the variables
x∈R
-(5/2(8x+2)-2)-13=0
We multiply all the terms by the denominator
-(5-13*2(8x+2)-2)=0
We calculate terms in parentheses: -(5-13*2(8x+2)-2), so:We add all the numbers together, and all the variables
5-13*2(8x+2)-2
determiningTheFunctionDomain -13*2(8x+2)+5-2
We add all the numbers together, and all the variables
-13*2(8x+2)+3
Wy multiply elements
-26x(8+3
Back to the equation:
-(-26x(8+3)
-(-26x11=0
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