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-13x+36-x2=0
We add all the numbers together, and all the variables
-1x^2-13x+36=0
a = -1; b = -13; c = +36;
Δ = b2-4ac
Δ = -132-4·(-1)·36
Δ = 313
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{313}}{2*-1}=\frac{13-\sqrt{313}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{313}}{2*-1}=\frac{13+\sqrt{313}}{-2} $
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