-13x-6(3-3x)=3(x-2)-16

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Solution for -13x-6(3-3x)=3(x-2)-16 equation: 



-13x-6(3-3x)=3(x-2)-16

We move all terms to the left:

-13x-6(3-3x)-(3(x-2)-16)=0

We add all the numbers together, and all the variables

-13x-6(-3x+3)-(3(x-2)-16)=0

We multiply parentheses

-13x+18x-(3(x-2)-16)-18=0



We calculate terms in parentheses: -(3(x-2)-16), so:

3(x-2)-16

We multiply parentheses

3x-6-16

We add all the numbers together, and all the variables

3x-22

Back to the equation:

-(3x-22)



We add all the numbers together, and all the variables

5x-(3x-22)-18=0

We get rid of parentheses

5x-3x+22-18=0

We add all the numbers together, and all the variables

2x+4=0

We move all terms containing x to the left, all other terms to the right

2x=-4

x=-4/2

x=-2

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