-14((6-2y)/7)-4y=-2

Solution for -14((6-2y)/7)-4y=-2 equation:

-14((6-2y)/7)-4y=-2

We move all terms to the left:

-14((6-2y)/7)-4y-(-2)=0

We add all the numbers together, and all the variables

-14((-2y+6)/7)-4y-(-2)=0

We add all the numbers together, and all the variables

-4y-14((-2y+6)/7)+2=0

We multiply all the terms by the denominator


-4y*7)-14((-2y+6)+2*7)=0

We add all the numbers together, and all the variables

-4y*7)-14((-2y+6)=0

Wy multiply elements

-28y^2=0

a = -28; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-28)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{-56}=0$