-14((6-2y)/7)-4y=-2

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Solution for -14((6-2y)/7)-4y=-2 equation:



-14((6-2y)/7)-4y=-2
We move all terms to the left:
-14((6-2y)/7)-4y-(-2)=0
We add all the numbers together, and all the variables
-14((-2y+6)/7)-4y-(-2)=0
We add all the numbers together, and all the variables
-4y-14((-2y+6)/7)+2=0
We multiply all the terms by the denominator
-4y*7)-14((-2y+6)+2*7)=0
We add all the numbers together, and all the variables
-4y*7)-14((-2y+6)=0
Wy multiply elements
-28y^2=0
a = -28; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-28)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{-56}=0$

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