-14(z+3)+5(4z-4)=5(z-4)+11

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Solution for -14(z+3)+5(4z-4)=5(z-4)+11 equation: 



-14(z+3)+5(4z-4)=5(z-4)+11

We move all terms to the left:

-14(z+3)+5(4z-4)-(5(z-4)+11)=0

We multiply parentheses

-14z+20z-(5(z-4)+11)-42-20=0



We calculate terms in parentheses: -(5(z-4)+11), so:

5(z-4)+11

We multiply parentheses

5z-20+11

We add all the numbers together, and all the variables

5z-9

Back to the equation:

-(5z-9)



We add all the numbers together, and all the variables

6z-(5z-9)-62=0

We get rid of parentheses

6z-5z+9-62=0

We add all the numbers together, and all the variables

z-53=0

We move all terms containing z to the left, all other terms to the right

z=53

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