-14(z+3)=6(3z-7)=3(z-6)+9

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Solution for -14(z+3)=6(3z-7)=3(z-6)+9 equation: 



-14(z+3)=6(3z-7)=3(z-6)+9

We move all terms to the left:

-14(z+3)-(6(3z-7))=0

We multiply parentheses

-14z-(6(3z-7))-42=0



We calculate terms in parentheses: -(6(3z-7)), so:

6(3z-7)

We multiply parentheses

18z-42

Back to the equation:

-(18z-42)



We get rid of parentheses

-14z-18z+42-42=0

We add all the numbers together, and all the variables

-32z=0

z=0/-32

z=0

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