-14(z-5)=-14z+70-14(z-5)=-14z+70

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Solution for -14(z-5)=-14z+70-14(z-5)=-14z+70 equation: 



-14(z-5)=-14z+70-14(z-5)=-14z+70

We move all terms to the left:

-14(z-5)-(-14z+70-14(z-5))=0

We multiply parentheses

-14z-(-14z+70-14(z-5))+70=0



We calculate terms in parentheses: -(-14z+70-14(z-5)), so:

-14z+70-14(z-5)

determiningTheFunctionDomain
-14z-14(z-5)+70

We multiply parentheses

-14z-14z+70+70

We add all the numbers together, and all the variables

-28z+140

Back to the equation:

-(-28z+140)



We get rid of parentheses

-14z+28z-140+70=0

We add all the numbers together, and all the variables

14z-70=0

We move all terms containing z to the left, all other terms to the right

14z=70

z=70/14

z=5

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