-14+(3-5x)-(1-x)=4x-2(x-3)

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Solution for -14+(3-5x)-(1-x)=4x-2(x-3) equation: 



-14+(3-5x)-(1-x)=4x-2(x-3)

We move all terms to the left:

-14+(3-5x)-(1-x)-(4x-2(x-3))=0

We add all the numbers together, and all the variables

(-5x+3)-(-1x+1)-(4x-2(x-3))-14=0

We get rid of parentheses

-5x+1x-(4x-2(x-3))+3-1-14=0



We calculate terms in parentheses: -(4x-2(x-3)), so:

4x-2(x-3)

We multiply parentheses

4x-2x+6

We add all the numbers together, and all the variables

2x+6

Back to the equation:

-(2x+6)



We add all the numbers together, and all the variables

-4x-(2x+6)-12=0

We get rid of parentheses

-4x-2x-6-12=0

We add all the numbers together, and all the variables

-6x-18=0

We move all terms containing x to the left, all other terms to the right

-6x=18

x=18/-6

x=-3

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