-14+12d=4d+2(d-3)+22

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Solution for -14+12d=4d+2(d-3)+22 equation: 



-14+12d=4d+2(d-3)+22

We move all terms to the left:

-14+12d-(4d+2(d-3)+22)=0



We calculate terms in parentheses: -(4d+2(d-3)+22), so:

4d+2(d-3)+22

We multiply parentheses

4d+2d-6+22

We add all the numbers together, and all the variables

6d+16

Back to the equation:

-(6d+16)



We get rid of parentheses

12d-6d-16-14=0

We add all the numbers together, and all the variables

6d-30=0

We move all terms containing d to the left, all other terms to the right

6d=30

d=30/6

d=5

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