-14+2(z-3)=6(z+3)-2z

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Solution for -14+2(z-3)=6(z+3)-2z equation: 



-14+2(z-3)=6(z+3)-2z

We move all terms to the left:

-14+2(z-3)-(6(z+3)-2z)=0

We multiply parentheses

2z-(6(z+3)-2z)-6-14=0



We calculate terms in parentheses: -(6(z+3)-2z), so:

6(z+3)-2z

We add all the numbers together, and all the variables

-2z+6(z+3)

We multiply parentheses

-2z+6z+18

We add all the numbers together, and all the variables

4z+18

Back to the equation:

-(4z+18)



We add all the numbers together, and all the variables

2z-(4z+18)-20=0

We get rid of parentheses

2z-4z-18-20=0

We add all the numbers together, and all the variables

-2z-38=0

We move all terms containing z to the left, all other terms to the right

-2z=38

z=38/-2

z=-19

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