-14+2x+x=3(x-2)-8

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Solution for -14+2x+x=3(x-2)-8 equation:



-14+2x+x=3(x-2)-8
We move all terms to the left:
-14+2x+x-(3(x-2)-8)=0
We add all the numbers together, and all the variables
3x-(3(x-2)-8)-14=0
We calculate terms in parentheses: -(3(x-2)-8), so:
3(x-2)-8
We multiply parentheses
3x-6-8
We add all the numbers together, and all the variables
3x-14
Back to the equation:
-(3x-14)
We get rid of parentheses
3x-3x+14-14=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0

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