-14+3(n+10)=7(2n+4)+n

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Solution for -14+3(n+10)=7(2n+4)+n equation: 



-14+3(n+10)=7(2n+4)+n

We move all terms to the left:

-14+3(n+10)-(7(2n+4)+n)=0

We multiply parentheses

3n-(7(2n+4)+n)+30-14=0



We calculate terms in parentheses: -(7(2n+4)+n), so:

7(2n+4)+n

We add all the numbers together, and all the variables

n+7(2n+4)

We multiply parentheses

n+14n+28

We add all the numbers together, and all the variables

15n+28

Back to the equation:

-(15n+28)



We add all the numbers together, and all the variables

3n-(15n+28)+16=0

We get rid of parentheses

3n-15n-28+16=0

We add all the numbers together, and all the variables

-12n-12=0

We move all terms containing n to the left, all other terms to the right

-12n=12

n=12/-12

n=-1

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