-14+3(x+10)=7(2x-4)+x

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Solution for -14+3(x+10)=7(2x-4)+x equation: 



-14+3(x+10)=7(2x-4)+x

We move all terms to the left:

-14+3(x+10)-(7(2x-4)+x)=0

We multiply parentheses

3x-(7(2x-4)+x)+30-14=0



We calculate terms in parentheses: -(7(2x-4)+x), so:

7(2x-4)+x

We add all the numbers together, and all the variables

x+7(2x-4)

We multiply parentheses

x+14x-28

We add all the numbers together, and all the variables

15x-28

Back to the equation:

-(15x-28)



We add all the numbers together, and all the variables

3x-(15x-28)+16=0

We get rid of parentheses

3x-15x+28+16=0

We add all the numbers together, and all the variables

-12x+44=0

We move all terms containing x to the left, all other terms to the right

-12x=-44

x=-44/-12

x=3+2/3

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