-14+3(x-10)=7(2x+5)+x

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Solution for -14+3(x-10)=7(2x+5)+x equation: 



-14+3(x-10)=7(2x+5)+x

We move all terms to the left:

-14+3(x-10)-(7(2x+5)+x)=0

We multiply parentheses

3x-(7(2x+5)+x)-30-14=0



We calculate terms in parentheses: -(7(2x+5)+x), so:

7(2x+5)+x

We add all the numbers together, and all the variables

x+7(2x+5)

We multiply parentheses

x+14x+35

We add all the numbers together, and all the variables

15x+35

Back to the equation:

-(15x+35)



We add all the numbers together, and all the variables

3x-(15x+35)-44=0

We get rid of parentheses

3x-15x-35-44=0

We add all the numbers together, and all the variables

-12x-79=0

We move all terms containing x to the left, all other terms to the right

-12x=79

x=79/-12

x=-6+7/12

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