-142=3-5(8b-3)

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Solution for -142=3-5(8b-3) equation: 



-142=3-5(8b-3)

We move all terms to the left:

-142-(3-5(8b-3))=0



We calculate terms in parentheses: -(3-5(8b-3)), so:

3-5(8b-3)

determiningTheFunctionDomain
-5(8b-3)+3

We multiply parentheses

-40b+15+3

We add all the numbers together, and all the variables

-40b+18

Back to the equation:

-(-40b+18)



We get rid of parentheses

40b-18-142=0

We add all the numbers together, and all the variables

40b-160=0

We move all terms containing b to the left, all other terms to the right

40b=160

b=160/40

b=4

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