-14=(2(h-3))/5

Solution for -14=(2(h-3))/5 equation:

-14=(2(h-3))/5

We move all terms to the left:

-14-((2(h-3))/5)=0

We multiply all the terms by the denominator


-((2(h-3))-14*5)=0


We calculate terms in parentheses: -((2(h-3))-14*5), so:

(2(h-3))-14*5

We add all the numbers together, and all the variables

(2(h-3))-70


We calculate terms in parentheses: +(2(h-3)), so:

2(h-3)

We multiply parentheses

2h-6

Back to the equation:

+(2h-6)


We get rid of parentheses

2h-6-70

We add all the numbers together, and all the variables

2h-76

Back to the equation:

-(2h-76)


We get rid of parentheses

-2h+76=0

We move all terms containing h to the left, all other terms to the right

-2h=-76

h=-76/-2

h=+38