-14x+2(3x-4)=4(x-2)+2x

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Solution for -14x+2(3x-4)=4(x-2)+2x equation: 



-14x+2(3x-4)=4(x-2)+2x

We move all terms to the left:

-14x+2(3x-4)-(4(x-2)+2x)=0

We multiply parentheses

-14x+6x-(4(x-2)+2x)-8=0



We calculate terms in parentheses: -(4(x-2)+2x), so:

4(x-2)+2x

We add all the numbers together, and all the variables

2x+4(x-2)

We multiply parentheses

2x+4x-8

We add all the numbers together, and all the variables

6x-8

Back to the equation:

-(6x-8)



We add all the numbers together, and all the variables

-8x-(6x-8)-8=0

We get rid of parentheses

-8x-6x+8-8=0

We add all the numbers together, and all the variables

-14x=0

x=0/-14

x=0

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