-14z2+35z=0

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Solution for -14z2+35z=0 equation:



-14z^2+35z=0
a = -14; b = 35; c = 0;
Δ = b2-4ac
Δ = 352-4·(-14)·0
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-35}{2*-14}=\frac{-70}{-28} =2+1/2 $
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+35}{2*-14}=\frac{0}{-28} =0 $

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