-15(y+1)+5(4y-4)=4(y-4)+9

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Solution for -15(y+1)+5(4y-4)=4(y-4)+9 equation: 



-15(y+1)+5(4y-4)=4(y-4)+9

We move all terms to the left:

-15(y+1)+5(4y-4)-(4(y-4)+9)=0

We multiply parentheses

-15y+20y-(4(y-4)+9)-15-20=0



We calculate terms in parentheses: -(4(y-4)+9), so:

4(y-4)+9

We multiply parentheses

4y-16+9

We add all the numbers together, and all the variables

4y-7

Back to the equation:

-(4y-7)



We add all the numbers together, and all the variables

5y-(4y-7)-35=0

We get rid of parentheses

5y-4y+7-35=0

We add all the numbers together, and all the variables

y-28=0

We move all terms containing y to the left, all other terms to the right

y=28

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