-15(z+2)+5(4z-7)=4(z-3)+9

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Solution for -15(z+2)+5(4z-7)=4(z-3)+9 equation:



-15(z+2)+5(4z-7)=4(z-3)+9
We move all terms to the left:
-15(z+2)+5(4z-7)-(4(z-3)+9)=0
We multiply parentheses
-15z+20z-(4(z-3)+9)-30-35=0
We calculate terms in parentheses: -(4(z-3)+9), so:
4(z-3)+9
We multiply parentheses
4z-12+9
We add all the numbers together, and all the variables
4z-3
Back to the equation:
-(4z-3)
We add all the numbers together, and all the variables
5z-(4z-3)-65=0
We get rid of parentheses
5z-4z+3-65=0
We add all the numbers together, and all the variables
z-62=0
We move all terms containing z to the left, all other terms to the right
z=62

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