-15+3(b+2)+4(b+1)=2

Solution for -15+3(b+2)+4(b+1)=2 equation:

Simplifying
-15 + 3(b + 2) + 4(b + 1) = 2

Reorder the terms:
-15 + 3(2 + b) + 4(b + 1) = 2
-15 + (2 * 3 + b * 3) + 4(b + 1) = 2
-15 + (6 + 3b) + 4(b + 1) = 2

Reorder the terms:
-15 + 6 + 3b + 4(1 + b) = 2
-15 + 6 + 3b + (1 * 4 + b * 4) = 2
-15 + 6 + 3b + (4 + 4b) = 2

Reorder the terms:
-15 + 6 + 4 + 3b + 4b = 2

Combine like terms: -15 + 6 = -9
-9 + 4 + 3b + 4b = 2

Combine like terms: -9 + 4 = -5
-5 + 3b + 4b = 2

Combine like terms: 3b + 4b = 7b
-5 + 7b = 2

Solving
-5 + 7b = 2

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + 7b = 2 + 5

Combine like terms: -5 + 5 = 0
0 + 7b = 2 + 5
7b = 2 + 5

Combine like terms: 2 + 5 = 7
7b = 7

Divide each side by '7'.
b = 1

Simplifying
b = 1