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-15+3=1/3(9-15x)
We move all terms to the left:
-15+3-(1/3(9-15x))=0
Domain of the equation: 3(9-15x))!=0We add all the numbers together, and all the variables
x∈R
-(1/3(-15x+9))-15+3=0
We add all the numbers together, and all the variables
-(1/3(-15x+9))-12=0
We multiply all the terms by the denominator
-(1-12*3(-15x+9))=0
We calculate terms in parentheses: -(1-12*3(-15x+9)), so:
1-12*3(-15x+9)
determiningTheFunctionDomain -12*3(-15x+9)+1
Wy multiply elements
-36x(-+1
We use the square of the difference formula
-36x(-1
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