-15+4/5p=p

Solution for -15+4/5p=p equation:

-15+4/5p=p

We move all terms to the left:

-15+4/5p-(p)=0


Domain of the equation: 5p!=0

p!=0/5

p!=0

p∈R


We add all the numbers together, and all the variables

-1p+4/5p-15=0

We multiply all the terms by the denominator


-1p*5p-15*5p+4=0

Wy multiply elements

-5p^2-75p+4=0

a = -5; b = -75; c = +4;
Δ = b2-4ac
Δ = -752-4·(-5)·4
Δ = 5705
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-75)-\sqrt{5705}}{2*-5}=\frac{75-\sqrt{5705}}{-10}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-75)+\sqrt{5705}}{2*-5}=\frac{75+\sqrt{5705}}{-10}
$