-15+y=2(4y-5)+30

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Solution for -15+y=2(4y-5)+30 equation: 



-15+y=2(4y-5)+30

We move all terms to the left:

-15+y-(2(4y-5)+30)=0



We calculate terms in parentheses: -(2(4y-5)+30), so:

2(4y-5)+30

We multiply parentheses

8y-10+30

We add all the numbers together, and all the variables

8y+20

Back to the equation:

-(8y+20)



We get rid of parentheses

y-8y-20-15=0

We add all the numbers together, and all the variables

-7y-35=0

We move all terms containing y to the left, all other terms to the right

-7y=35

y=35/-7

y=-5

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