-152=3(-1-6v)-5

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Solution for -152=3(-1-6v)-5 equation: 



-152=3(-1-6v)-5

We move all terms to the left:

-152-(3(-1-6v)-5)=0

We add all the numbers together, and all the variables

-(3(-6v-1)-5)-152=0



We calculate terms in parentheses: -(3(-6v-1)-5), so:

3(-6v-1)-5

We multiply parentheses

-18v-3-5

We add all the numbers together, and all the variables

-18v-8

Back to the equation:

-(-18v-8)



We get rid of parentheses

18v+8-152=0

We add all the numbers together, and all the variables

18v-144=0

We move all terms containing v to the left, all other terms to the right

18v=144

v=144/18

v=8

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