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-15=3(4-h+1)+5-2h
We move all terms to the left:
-15-(3(4-h+1)+5-2h)=0
We add all the numbers together, and all the variables
-(3(-1h+5)+5-2h)-15=0
We calculate terms in parentheses: -(3(-1h+5)+5-2h), so:We get rid of parentheses
3(-1h+5)+5-2h
determiningTheFunctionDomain 3(-1h+5)-2h+5
We add all the numbers together, and all the variables
-2h+3(-1h+5)+5
We multiply parentheses
-2h-3h+15+5
We add all the numbers together, and all the variables
-5h+20
Back to the equation:
-(-5h+20)
5h-20-15=0
We add all the numbers together, and all the variables
5h-35=0
We move all terms containing h to the left, all other terms to the right
5h=35
h=35/5
h=7
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