-15x+50=(5x-2x-40)/5

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Solution for -15x+50=(5x-2x-40)/5 equation: 



-15x+50=(5x-2x-40)/5

We move all terms to the left:

-15x+50-((5x-2x-40)/5)=0

We add all the numbers together, and all the variables

-15x-((3x-40)/5)+50=0

We multiply all the terms by the denominator


-15x*5)-((3x-40)+50*5)=0

We add all the numbers together, and all the variables

-15x*5)-((3x-40)=0

Wy multiply elements

-75x^2=0

a = -75; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-75)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-150}=0$

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