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-15x=-12x(x-1)
We move all terms to the left:
-15x-(-12x(x-1))=0
We calculate terms in parentheses: -(-12x(x-1)), so:We get rid of parentheses
-12x(x-1)
We multiply parentheses
-12x^2+12x
Back to the equation:
-(-12x^2+12x)
12x^2-12x-15x=0
We add all the numbers together, and all the variables
12x^2-27x=0
a = 12; b = -27; c = 0;
Δ = b2-4ac
Δ = -272-4·12·0
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-27}{2*12}=\frac{0}{24} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+27}{2*12}=\frac{54}{24} =2+1/4 $
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