-16(1x-4)=-2(8x-32)

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Solution for -16(1x-4)=-2(8x-32) equation: 


Simplifying
-16(1x + -4) = -2(8x + -32)

Reorder the terms:
-16(-4 + 1x) = -2(8x + -32)
(-4 * -16 + 1x * -16) = -2(8x + -32)
(64 + -16x) = -2(8x + -32)

Reorder the terms:
64 + -16x = -2(-32 + 8x)
64 + -16x = (-32 * -2 + 8x * -2)
64 + -16x = (64 + -16x)

Add '-64' to each side of the equation.
64 + -64 + -16x = 64 + -64 + -16x

Combine like terms: 64 + -64 = 0
0 + -16x = 64 + -64 + -16x
-16x = 64 + -64 + -16x

Combine like terms: 64 + -64 = 0
-16x = 0 + -16x
-16x = -16x

Add '16x' to each side of the equation.
-16x + 16x = -16x + 16x

Combine like terms: -16x + 16x = 0
0 = -16x + 16x

Combine like terms: -16x + 16x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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