-16(x-1/2)(x+3)=0

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Solution for -16(x-1/2)(x+3)=0 equation: 



-16(x-1/2)(x+3)=0



Domain of the equation: 2)(x+3)!=0

x∈R



We add all the numbers together, and all the variables

-16(+x-1/2)(x+3)=0

We multiply parentheses ..

-16(+x^2+3x-1x^2-1/2*3)=0

We multiply all the terms by the denominator


-16(+x^2+3x-1x^2-1=0

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