-16(y+1)+5(4y-4)=3(y-4)+8

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Solution for -16(y+1)+5(4y-4)=3(y-4)+8 equation: 



-16(y+1)+5(4y-4)=3(y-4)+8

We move all terms to the left:

-16(y+1)+5(4y-4)-(3(y-4)+8)=0

We multiply parentheses

-16y+20y-(3(y-4)+8)-16-20=0



We calculate terms in parentheses: -(3(y-4)+8), so:

3(y-4)+8

We multiply parentheses

3y-12+8

We add all the numbers together, and all the variables

3y-4

Back to the equation:

-(3y-4)



We add all the numbers together, and all the variables

4y-(3y-4)-36=0

We get rid of parentheses

4y-3y+4-36=0

We add all the numbers together, and all the variables

y-32=0

We move all terms containing y to the left, all other terms to the right

y=32

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