-16(y+1)=8(6y-2)-128

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Solution for -16(y+1)=8(6y-2)-128 equation:


Simplifying
-16(y + 1) = 8(6y + -2) + -128

Reorder the terms:
-16(1 + y) = 8(6y + -2) + -128
(1 * -16 + y * -16) = 8(6y + -2) + -128
(-16 + -16y) = 8(6y + -2) + -128

Reorder the terms:
-16 + -16y = 8(-2 + 6y) + -128
-16 + -16y = (-2 * 8 + 6y * 8) + -128
-16 + -16y = (-16 + 48y) + -128

Reorder the terms:
-16 + -16y = -16 + -128 + 48y

Combine like terms: -16 + -128 = -144
-16 + -16y = -144 + 48y

Solving
-16 + -16y = -144 + 48y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-48y' to each side of the equation.
-16 + -16y + -48y = -144 + 48y + -48y

Combine like terms: -16y + -48y = -64y
-16 + -64y = -144 + 48y + -48y

Combine like terms: 48y + -48y = 0
-16 + -64y = -144 + 0
-16 + -64y = -144

Add '16' to each side of the equation.
-16 + 16 + -64y = -144 + 16

Combine like terms: -16 + 16 = 0
0 + -64y = -144 + 16
-64y = -144 + 16

Combine like terms: -144 + 16 = -128
-64y = -128

Divide each side by '-64'.
y = 2

Simplifying
y = 2

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