-16(y+3)+5(4y-3)=3(y-5)+12

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Solution for -16(y+3)+5(4y-3)=3(y-5)+12 equation: 



-16(y+3)+5(4y-3)=3(y-5)+12

We move all terms to the left:

-16(y+3)+5(4y-3)-(3(y-5)+12)=0

We multiply parentheses

-16y+20y-(3(y-5)+12)-48-15=0



We calculate terms in parentheses: -(3(y-5)+12), so:

3(y-5)+12

We multiply parentheses

3y-15+12

We add all the numbers together, and all the variables

3y-3

Back to the equation:

-(3y-3)



We add all the numbers together, and all the variables

4y-(3y-3)-63=0

We get rid of parentheses

4y-3y+3-63=0

We add all the numbers together, and all the variables

y-60=0

We move all terms containing y to the left, all other terms to the right

y=60

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