-16+6(z-12)=2(z-8)+4z-12

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Solution for -16+6(z-12)=2(z-8)+4z-12 equation: 


Simplifying
-16 + 6(z + -12) = 2(z + -8) + 4z + -12

Reorder the terms:
-16 + 6(-12 + z) = 2(z + -8) + 4z + -12
-16 + (-12 * 6 + z * 6) = 2(z + -8) + 4z + -12
-16 + (-72 + 6z) = 2(z + -8) + 4z + -12

Combine like terms: -16 + -72 = -88
-88 + 6z = 2(z + -8) + 4z + -12

Reorder the terms:
-88 + 6z = 2(-8 + z) + 4z + -12
-88 + 6z = (-8 * 2 + z * 2) + 4z + -12
-88 + 6z = (-16 + 2z) + 4z + -12

Reorder the terms:
-88 + 6z = -16 + -12 + 2z + 4z

Combine like terms: -16 + -12 = -28
-88 + 6z = -28 + 2z + 4z

Combine like terms: 2z + 4z = 6z
-88 + 6z = -28 + 6z

Add '-6z' to each side of the equation.
-88 + 6z + -6z = -28 + 6z + -6z

Combine like terms: 6z + -6z = 0
-88 + 0 = -28 + 6z + -6z
-88 = -28 + 6z + -6z

Combine like terms: 6z + -6z = 0
-88 = -28 + 0
-88 = -28

Solving
-88 = -28

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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