-16-3(a-4)+7a-3=10

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Solution for -16-3(a-4)+7a-3=10 equation: 



-16-3(a-4)+7a-3=10

We move all terms to the left:

-16-3(a-4)+7a-3-(10)=0

We add all the numbers together, and all the variables

7a-3(a-4)-29=0

We multiply parentheses

7a-3a+12-29=0

We add all the numbers together, and all the variables

4a-17=0

We move all terms containing a to the left, all other terms to the right

4a=17

a=17/4

a=4+1/4

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