-16/9-n+1/3(4-n)=-4/3(3+n)

Solution for -16/9-n+1/3(4-n)=-4/3(3+n) equation:

-16/9-n+1/3(4-n)=-4/3(3+n)

We move all terms to the left:

-16/9-n+1/3(4-n)-(-4/3(3+n))=0


Domain of the equation: 3(4-n)!=0

n∈R



Domain of the equation: 3(3+n))!=0

n∈R


We add all the numbers together, and all the variables

-n+1/3(-1n+4)-(-4/3(n+3))-16/9=0

We add all the numbers together, and all the variables

-1n+1/3(-1n+4)-(-4/3(n+3))-16/9=0

We calculate fractions


(-144n^2(-)/(3(-1n+4)*3(n+3))*9)-1n+(27nn/(3(-1n+4)*3(n+3))*9)+(-(-4*3(-1n+4)*9)/(3(-1n+4)*3(n+3))*9)=0


We calculate terms in parentheses: +(-144n^2(-)/(3(-1n+4)*3(n+3))*9), so:

-144n^2(-)/(3(-1n+4)*3(n+3))*9

We add all the numbers together, and all the variables

-144n^20/(3(-1n+4)*3(n+3))*9

We multiply all the terms by the denominator


-144n^20

We do not support enpression: n^20