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-16X^2+46X+6=0
a = -16; b = 46; c = +6;
Δ = b2-4ac
Δ = 462-4·(-16)·6
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(46)-50}{2*-16}=\frac{-96}{-32} =+3 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(46)+50}{2*-16}=\frac{4}{-32} =-1/8 $
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