-16n2+56n=0

Solution for -16n2+56n=0 equation:

-16n^2+56n=0

a = -16; b = 56; c = 0;
Δ = b2-4ac
Δ = 562-4·(-16)·0
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-56}{2*-16}=\frac{-112}{-32}
=3+1/2
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+56}{2*-16}=\frac{0}{-32}
=0
$